55.There are three friends x,y,z . They go to excursion with their girl friends. There they wanted to find weights but their GF’s are not accept to check their weight. Then they check weights as x,y,z individually and then x and y, y and z,x and z , then all(x,y,z) , the last measure is 171. Then find the average of all these seven measures.

• x+y+z=171
  total of seven weights = x + y +z + (x+y) + (y+z) + (z+x) + (x+y+z)
  =4(x+y+z)
  =4*171
  =684
  avg of seven weights = 684/7
  = 97.71
• 11 years agoHelpfull: Yes(18) No(0)
• 684/7
  as avg yields to 4(x+y+z)/7
  and x+y+z=171
• 11 years agoHelpfull: Yes(2) No(1)