59.An equation of the form 4x+6y-2z =32. Find the difference between x intercept and z intercept

• given equation 4x+6y-2z=32
  (4/32)x+(6/32)y-2z=1
  thus,x-intercept=8,y-intercept=16/3
  and z-intercept=-16
  hence difference between x-intercept and z-intercept=8-(-16)
  =24
• 11 years agoHelpfull: Yes(8) No(0)
• Given equation is 4x+6y-2z=32.
  so, 4x/32+6y/32-2z/32=1
  x=8,y=16/3,z=-16
  Difference between x intercept and z intercept=(8)-(-16)=8+16=24.
• 11 years agoHelpfull: Yes(3) No(0)
• x/8 + 6y/32 - z/16 = 1
  => x intercept=8
  y intercept= -16/3
  
  so difference is 8+16/3=40/3
  Ans is 40/3.
• 11 years agoHelpfull: Yes(1) No(12)