77. An equation of the form 7x+17y+3z=54. Find the difference between x intercept and z intercept?

• we write the equation 7x+17y+3z=54 in the intercept form
  (7x/54)+(17y/54)+(3z/54)=1
  => (x/54/7)+(y/54/17)+(z/18)=1
  x-intercept=54/7 and z-intercept=18
  diff=x-intercept-z-intercept
  => 54/7-18
  -72/7
• 11 years agoHelpfull: Yes(9) No(1)
• given eq can b written as x/(54/7)+y/(54/17)+z/(54/3)=1
  which is in d form of x/a+y/b+z/c=1
  where x intercept a =54/7, z intercept c=54/3=18
  hence ans=a~b=(54/7)~18= 72/7
• 11 years agoHelpfull: Yes(3) No(0)
• (x/(54/7))+(y/(54/17))+(z/(54/3))=1
  x intercept=54/7;y intercept=54/17;z intercept=54/3
  difference b/w x intercept and z intercept=(54/7)-(54/3)
  =-216/21=-72/7
  so the ans is -72/7
• 11 years agoHelpfull: Yes(0) No(0)
• given equation..,7x+17y+3z=54 is
  (7x/54)+(17y/54)+(3z/54)=1
  => (x/54/7)+(y/54/17)+(z/18)=1
  x-intercept=54/7 n z-intercept=18
  diff=x-intercept-z-intercept
  = 54/7-18
  = -72/7
• 11 years agoHelpfull: Yes(0) No(0)
• given equation..,7x+17y+3z=54 is
  (7x/54)+(17y/54)+(3z/54)=1
  => (x/54/7)+(y/54/17)+(z/18)=1
  x-intercept=54/7 n z-intercept=18
  diff=x-intercept-z-intercept
  = 54/7-18
  = -72/7
• 11 years agoHelpfull: Yes(0) No(0)