105 A girl has to make pizza with different toppings There are 8 different toppings in how many ways can

The number of ways of choosing r distinct objects from n distinct objects is given by the formula
C(n, r) = n!/r!*(n-r)!
where n! = n(n-1)(n-2).......3*2*1

If order was important, the number of arrangements is
P(n,r) n!/(n-r)!

Now suppose you wanted to display one topping in the middle and the other around the edge, you would be considering arrangements and the answer would be
P(8, 2) = 8!/6!
= 8*7
= 56

However, suppose that you wish to sprinkle toppings randomly over the pizza base. Since it does not matter what the arrangements are, the number of ways is
C(8, 2) = 8! / 2!*6!
= 8*7 / 2*1
= 56/2
= 28
11 years agoHelpfull: Yes(11) No(0)
8*7=56 ways....
11 years agoHelpfull: Yes(3) No(7)
28
because 1 topping have 7 options.
2 topping have 6 poptions.
3 topping have 5 options...............and so on so sum of 7+6+5+4+3+2+1=28
11 years agoHelpfull: Yes(3) No(0)
28
8c2=8!/(2!*(8-2)!)
11 years agoHelpfull: Yes(1) No(0)
8 items n we select 2 so,
8c2=28
11 years agoHelpfull: Yes(1) No(0)
7! ie 5040
11 years agoHelpfull: Yes(0) No(9)
100%
because she already make by 8 different ways...
11 years agoHelpfull: Yes(0) No(3)
there are 8 toppings have to make with 2 different toppings so the number of ways are 8c2=16
11 years agoHelpfull: Yes(0) No(4)
C(n, r) = n!/r!*(n-r)!
c(8,2)=8!/2!*(8-2)!=28
11 years agoHelpfull: Yes(0) No(0)
56, first she can makes by 8 ways &
second she can makes by 7 ways
so 8*7=56
11 years agoHelpfull: Yes(0) No(5)
28... c(8,2)
11 years agoHelpfull: Yes(0) No(0)

105. A girl has to make pizza with different toppings . There are 8 different toppings, in how many ways can she make pizzas with 2 different toppings.