A car running at a speed of 50 kph crosses a platform double its length in 32.5 seconds.what is the length of the platform?

• Ans=300.926 m
  Speed of car=50km/hr=50000 m/3600 s
  If the length of car=x,then length of platform=2x,Total distance=3x
  Distance covered in 32.5 second=32.5*50000/3600=4062.5/9=3x, so x=4062.5/27
  length of platform=2x=4062.5*2/27=300.926 m
• 11 years agoHelpfull: Yes(6) No(0)
• 50*1000/3600 = 2x/32.5
  x=225.69m
• 11 years agoHelpfull: Yes(1) No(2)