If product P of 3 positive integers is 6 times their sum and one of the integers is the sum of other two, then the sum of all possible values of P is
A. 240
B. 360
C. 336
D. 432

• let x y z 3int
  x*y*z=6*(x+y+z)
  one int is sum of other two,so let x=y+z
  then,x*y*z=12x=>y*z=12
  possible values are y=1,z=12;=>x=13
  y=2,z=6;=>x=8
  y=3,z=4;=>x=7
  possible values of p are 156,96 and 84
  ans-336
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