Albert and Fernandez have a two lap swimming race. Both start from opposite ends of the pool. On the first lap, the boys pass each other at 18 m from the deep end of the pool. During the second lap they pass at 10 m from the shallow end of the pool. Both go at constant speed but one of them is faster. Each boy rests for 4 seconds at the end of the first lap. What is the length of the pool?
Ops: A. 50 m
B. 44 m
C. 48 m
D. 64 m

• B.44 Ans
  
  X-18/Sa=18/Sf...(i)
  (X+X-10)/Sa +4=(X+10)/Sf...(ii)
  Eq. (i) & (ii)
  
  we get X=44m
• 11 years agoHelpfull: Yes(1) No(0)