If 50 % of the 2 : 3 solution of milk and water is replaced with water, when the concentration of the solution is reduced by
(1) 25% (2) 33.3% (3) 50% (4) 75%

• Ans : (3) 50%
  Initial concentration 100*2/5=40%
  50% of solution has 1 part of milk and 1.5 part of water
  adding 2.5 parts of water(50% of initial mixture) will give 1 part of milk and 4 parts of water
  so concentration of solution is 100*1/5=20%
  Reduction in concentration = 100*(40-20)/40 = 50%
  
• 11 years agoHelpfull: Yes(2) No(0)