ram sells a table to shyam at a profit of 20% and shyam sells it at a profit of 30%.if it costs 3120 to sohan.the cost price of the table for ram is:

• Rs. 2000
  If the cost price of table for Ram=100
  Cost price for Shyam=100+100*20/100=120
  Cost price for sohan=120+120*30/100=156
  So 156% costed Rs. 3120,So its 100%=100*3120/156=2000
  
• 11 years agoHelpfull: Yes(10) No(0)
• c.p=(100/100+profit%)*s.p
  =(100/100+20)*3120
  =2600
• 11 years agoHelpfull: Yes(2) No(3)
• price for ram *(1.2) *(1.3)= 3120
  price for ram=2000
• 11 years agoHelpfull: Yes(1) No(0)
• it is tha case of succesive percentage
  20+30+20*30/100=56%
  x+x*56/100=3120
  x=2000 ans
• 10 years agoHelpfull: Yes(1) No(0)
• 2000,,,
  X+30X/100 =3120
  X=2400
  Y+20Y/100 =2400
  Y=2000.....
• 11 years agoHelpfull: Yes(0) No(0)
• Answer:
  Rs.2000.
  Let cost price of table for ram=x.
  Shyam's cost price=(x+20x/100)
  sohn's cost=3120=((x+(20x/100))*(30/100)) + (x+(20x/100))
  After solving,
  ==>x=2000
  
• 10 years agoHelpfull: Yes(0) No(0)