Eiden park is a cricket field while jubilee park is football field in MastNagar. In MastNagar all cricket fields are circular and football fields are rectangle or square.Among the boundary of all fields there are advertisement displays.In mastnagar length of advertisement displays must be same for all fields.Area of jubilee parks is 468m2.The farthest distance between any two points in jubilee park football field is 10sqrt10m.Find the approximate are of Eden park.
Options
A) 1936 m2 b)616 C)281 D) inadequate data

• @Sneha: Solution is here
  
  farthest distance= Diagnol
  if we assume jublie park as a square then result would be not match the side and the area, so this must be rectangular
  
  for rectangular
  area = l*b =468
  and l^2+b^2=1000 because diagonal=10sqrt10
  add 2lb both side
  l^2+b^2+2lb=1000+2lb
  (l+b)^2 = 1000+2*468
  l+b=sqrt1936----------------------------------------eq1
  
  as given already
  
  2*pi*r=2(l+b)
  
  pi*r=l+b-------------------------------eq2
  
  
  put the value of l+b in eq1
  
  pi*r=sqrt1936------------------------------ eq3
  
  area of circle = pi*r^2
  
  put the value of r here from eq3 616 will be answer
• 11 years agoHelpfull: Yes(38) No(1)
• ans B) 616
• 11 years agoHelpfull: Yes(8) No(0)
• Area=axb
  468=axb
  _________
  (10sqrt10)^2=a^2+b^2
  a^2+b^2=1000
  (a+b)^2=a^2+b^2+2ab
  on solving we get a+b=44, now perimeter=2(a+b)=> perimeter=88.
  now area=pi*r^2
  perimeter=2*(l+b)
  A=pi*r^2
  A=616m^2
• 11 years agoHelpfull: Yes(4) No(0)
• l*b=468
  l^2+b^2=1000
  on solving both equations by hit and trial, we get,
  l=26 and b=18
  l+b=44
  circumference of circle=circumference of rectangle
  2*(22/7)*r=2(44)
  on solving, r=14m
  so, area of circle= (22/7)*14*14
  area=616 square metres.
• 10 years agoHelpfull: Yes(2) No(0)
• Let us consider the football field to be rectangular with dimensions L X B. Even if the
  
  football field is square then we will get L = B.
  
  Given Area of jubilee park = 468sqm.
  
  Area of rect. park = LxB = 468 …… (i)
  
  Farthest distance of field is diagonal ;
  
  Therefore length of diagonal ; D = √L2+B2 = 10√10
  
  or L2+B2 = 1000 …….. (ii)
  
  Therefore; (L + B)2= L2+B2 + 2LB = 1000 + 2 x 468 = 1936
  
  or , (L+B) = √1936 = 44
  
  Therefore, Perimeter of rect. Field = 2 (L + B) = 2 x 44 = 88m
  
  a/c to question; Perimeter of rectangular field = Circumference of Circular field
  
  therefore, Circumference of Circular field = 2πR = 88m
  
  Radius of circular field = 14m
  
  Therefore Area of circular field = π142 = 616 sqm :-))
• 9 years agoHelpfull: Yes(1) No(0)
• @shweta how??
  
• 11 years agoHelpfull: Yes(0) No(0)
• Can somebody make it more clear that the jublie park is a rectangle and why it is not a square?
• 9 years agoHelpfull: Yes(0) No(0)