AC2,CG5,FL9,JR14,OY20,____

• ANS:UG27
  A+2=c,c+3=f........o+6=u(first letter)
  c+4=g,g+5=l........y+8=G(second letter)
  U=21,g=33,u+g=54/2=27 or 2+3=5,5+4=9,9+5=14,14+6=20,20+7=27(3rd letter)
• 11 years agoHelpfull: Yes(1) No(0)
• ans=UG27
  First letter: A+2=C;C+3=F;F+4=J;J+5=O; Next=> O+6=U
  Third digit: 2+3=5;5+4=9;9+5=14;14+6=20; Next=> 20+7=27
  Second letter: 2+1=3=C;5+2=7=G;9+3=12=L;14+4=18=R;20+5=25=Y; Next=> 27+6=33
  =(33-26)
  =7
  =G
• 11 years agoHelpfull: Yes(1) No(0)
• A=1,C=3 1+3=4/2=2..2+1=3=C(NEXT STARTING)
  2,5,9,14,20 DIFFERENCE OF 3,4,5,6 THEN 7... FIRST LETTER IS 21=T
  SO ANSWER IS ==== T(33RD ALPHABET)27....
  QUESTION IS WRONG.......
• 11 years agoHelpfull: Yes(0) No(2)
• zb27 before we have ac2=1+3/2=2,3+7=5 so cg5 and difference between is 3,4,5,6,7
  so we should get 27 as last so we have to get 54 so we should take alphabets which leads to a sum of 54 so i have taken z=26 and completing all alphabets and coming again from starting we get b=28 so 26+28/2=27
• 11 years agoHelpfull: Yes(0) No(1)