A solution of 25 liters contain 20% sugar, if 10 liters of the solution is evaporated, find the percentage of sugar in the final solution.

• it is 33.33%
  given 25 liters of sol has 20% sugar .
  qty of sugar =(20%/100%)*25 =5 lit of sugar
  (assume sugar qty in liter for easy calculation ).
  therefore 25 lit sol contain 20 lit of water and 5 liter of sugar .
  now the sol boils losing 10 liter of water .
  therefore the new 15 liter sol contains 10 liter water and 5 liter sugar . there new % of sugar is 5/15 * 100 =33.33%
• 13 years agoHelpfull: Yes(30) No(2)
• A solution of 25 liters contain 20% sugar.
  means it has 5 litres of sugar and 20 ltr of water.
  if 10 liters of the solution is evaporated, means 10 litres of water is evaporated, and 10 litres of water and 5 litres of sugar is left.
  
  then 100*5/15 =33.33 % of sugar is there in final solution.
• 13 years agoHelpfull: Yes(6) No(2)
• 33.33%
  20% of 25 liter=5liters i.e sugar volume
  10% of solution is evaporated i.e water only
  remaining solution = 15 liter that contain 5 liter sugar remain as prior solution
  5/15*100=33.33%
• 13 years agoHelpfull: Yes(2) No(0)
• 33.33
  25*20/100=5
  5*100/15=33.33
• 13 years agoHelpfull: Yes(2) No(0)
• it is 29.4%.
  in given solution,we have 20 liters of liquid and 5 liters sugar.
  so in 10 liters we have 8 liters of liquid and 2 liters sugar.
  so 8 liters of liquid is evaporated.
  now new solution is(20-8)liquid+(3+2)sugar.
  which is (12+5)=17 liters of solution.
  % of sugar in new solution is 5/17*100=29.41
• 13 years agoHelpfull: Yes(1) No(8)
• 20%
  2:8 ratio
  therefore if evap. is 10 ltrs of which 2 ltrs sugar and 8 ltrs water.
  so mix is 15ltrs and 3 ltrs sugar rest is water.
  3/15*100
• 13 years agoHelpfull: Yes(1) No(7)
• 33.33% suger in the final solution
• 13 years agoHelpfull: Yes(1) No(0)
• 13.04% remains .
• 13 years agoHelpfull: Yes(0) No(10)