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Maths Puzzle
how many 8 digit nos are there the sum of whose digit is even?
Read Solution (Total 3)
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- 43906250
All are even => (5^8 - 5^7) numbers ------------(1)
Here negative part 5^7 represents numbers with 0 as first digit
Two are odd => 8C2*(5^4)*5^6 - 7C2*(5^2)*5^5 -------------(2)
Four are odd => 8C4*(5^4)*5^4 - 7C4*(5^4)*5^3 -------------(3)
Six are odd => 8C6*(5^6)*5^2 - 7C6*(5^6)*5 ----------------(4)
All are odd => 5^8 -----------(5)
=> Total possibilities = (1) + (2) + (3) + (4) + (5)
= 43906250 ways - 11 years agoHelpfull: Yes(1) No(0)
- 9*10*10*10*10*10*10*5*5
- 11 years agoHelpfull: Yes(0) No(0)
- but ans is 45.10^6
- 11 years agoHelpfull: Yes(0) No(0)
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