A die is rolled and a coin is tossed. Find the probability that the die shows an odd number and the coin shows a head.

• The sample space S of the experiment described in question 5 is as follows
  
  S = { (1,H),(2,H),(3,H),(4,H),(5,H),(6,H)
  (1,T),(2,T),(3,T),(4,T),(5,T),(6,T)}
  Let E be the event "the die shows an odd number and the coin shows a head". Event E may be described as follows
  E={(1,H),(3,H),(5,H)}
  # The probability P(E) is given by
  P(E) = n(E) / n(S) = 3 / 12 = 1 / 4
• 11 years agoHelpfull: Yes(31) No(1)
• they are two independent events, p(a&b)=p(a)*p(b) when a&b are two independent events
  here p(a)= odd number prob= 3/6=1/2
  p(b)= coin show head= 1/2
  so ans= 1/2 * 1/2 = 1/4
• 11 years agoHelpfull: Yes(12) No(0)
• 1/4
  even tell
  even head
  odd tell
  odd head
  probability=1/4
  
• 11 years agoHelpfull: Yes(4) No(2)
• for coin 3/6=1/2 and for a head prob will be 1/2 .
  so 1/2 *1/2=1/4 is the answer.
• 11 years agoHelpfull: Yes(2) No(0)
• s={(1,H)(2,H)(3,H)(4,H)(5,H)(6,H)(1,T)(2,T)(3,T)(4,T)(5,T)(6,T)}
  no. of favorable outcomes=3
  total no. of outcomes=12
  p(the die shows odd number and the coin shows a head)=3/12=1/4
• 11 years agoHelpfull: Yes(1) No(0)
• ANS : 0.25
  No. of favourable outcomes = 3 [since there are 3 odd no.s and one head]
  Total no. of outcomes = 6*2 = 12
  Therefore required probability = no. of favourable outcomes/total outcomes
  = 3/12 = 1/4 = .25
• 11 years agoHelpfull: Yes(1) No(0)
• probability for die to show odd no. is 3/6=1/2
  and for coin to show head is 1/2.
  probability that die shows odd no. and coin a head is 1/2+1/2=1
  by the formula p(aub)=p(a)+p(b)
• 11 years agoHelpfull: Yes(1) No(0)
• s={(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)}
  no.of favourable outcomes=3
  total no.of outcomes=12
  probability=3/12=1/4
• 11 years agoHelpfull: Yes(0) No(0)
• for coin 3/6=1/2 and for a head prob will be 1/2 .
  'and'means multiply,so
  1/2 * 1/2 = 1/4
• 11 years agoHelpfull: Yes(0) No(0)
• p(odd)=1/6
  pair(1,t),(3,t),(5,t)
  p(t)=1/2
  p(0ddnumber&coin )= 1/6*1/2+1/6*1/2
  1/6*1/2
  3/12=1/4
  ans=1/4
  
• 11 years agoHelpfull: Yes(0) No(0)
• 6C3(combinations of odd no. from dice)*2C1(combination of heads from coin)..
• 11 years agoHelpfull: Yes(0) No(0)
• (1/2)*(3/6)= 1/4
• 11 years agoHelpfull: Yes(0) No(0)
• Let e be the event of getting a odd number from rolling a dice.
  therefore e={1,3,5},ans s be the sample space which is s={1,2,3,4,5,6}
  hence p(e)=3/6=1/2.
  and p(Tail)=1/2.
  as both connected with and operation so. total probability =1/2*1/2=1/4.
• 11 years agoHelpfull: Yes(0) No(0)
• sample space of throwing a die=6
  sample space of tossing a coin =2
  therefore event of getting an odd no and a head=3/6*1/2=1/4
• 11 years agoHelpfull: Yes(0) No(0)
• a die is rolled then tne probability that the die shows an odd number=3/6
  coin shows head=1/2
  he probability that the die shows an odd number and the coin shows a head=3/6*1/2=1/4
• 11 years agoHelpfull: Yes(0) No(0)