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Maths Puzzle
The gretest number which will divide 4003,4126 and 4249 , leaving the same remainder in each case is...
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- 4003 and 4126 are two different numbers
- 11 years agoHelpfull: Yes(3) No(0)
- it is 123
k-required number
r-remainder
consider first two numbers
4003=k*q1+r........(1)
4126=k*q2+r........(2)
from (1) and (2)
123=k(q1-q2)
k=123 at q1-q2
similarly check for 4126 and 4249 also for 4003 and 4249 by taking suitable value for q1-q2.
therefore the greatest number which will divide 4003,4126 & 4249. - 11 years agoHelpfull: Yes(2) No(1)
- 40029877
Let k be the number,r be the remainder
40034126 = k*q1 + r ----(1)
4249 = k*q2 + r --------(2)
(1) - (2) => 40029877 = k(q2-q1)
if (q2 - q1) = 1
=> k = greatest number = 40029877
- 11 years agoHelpfull: Yes(0) No(3)
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