The gretest number which will divide 4003,4126 and 4249 , leaving the same remainder in each case is...

• 4003 and 4126 are two different numbers
  
• 11 years agoHelpfull: Yes(3) No(0)
• it is 123
  k-required number
  r-remainder
  consider first two numbers
  4003=k*q1+r........(1)
  4126=k*q2+r........(2)
  from (1) and (2)
  123=k(q1-q2)
  k=123 at q1-q2
  similarly check for 4126 and 4249 also for 4003 and 4249 by taking suitable value for q1-q2.
  therefore the greatest number which will divide 4003,4126 & 4249.
• 11 years agoHelpfull: Yes(2) No(1)
• 40029877
  
  Let k be the number,r be the remainder
  40034126 = k*q1 + r ----(1)
  4249 = k*q2 + r --------(2)
  
  (1) - (2) => 40029877 = k(q2-q1)
  if (q2 - q1) = 1
  
  => k = greatest number = 40029877
  
• 11 years agoHelpfull: Yes(0) No(3)