how many 7 digit numbers are there that they have no repeating digit & not include digit 3 & 9?

• the number should consist of 8 digits, those are 0,1,2,4,5,6,7,8
  first digit of a number cant be 0;
  so the chances for 1st digit are 7(lets say digit 1 is placed)
  2nd digit are 7( bcoz 1 is alrdy used and 0 can be used i.e 0,2,4,5,6,7,8 )
  in the same way we shold proceed until the last digit....
  now the answer is 7*7*6*5*4*3*2=35280 numbers are possible
• 11 years agoHelpfull: Yes(38) No(0)
• Suppose the digits are ABCDEFG then,
  1) A can't acquire the value 0,3,9 and hence can be filled with remaining values in 7 ways.
  2)for the remaining digits 0 can be used.
  3) B can acquire any value within 0,1,2,4,5,6,7,8 excluding the value that is used for filling A.
  Similar argument goes for remaining digits.
  Hence answer is 7*7*6*5*4*3*2
• 11 years agoHelpfull: Yes(5) No(0)
• Ans: 35280
  
  possible Digits for 1st place= 7 ( 0,3,9 not allowed)
  possible Digits for 2nd place= 7 ( digit of 1st place ,3,9 not allowed)
  possible Digits for 3rd place= 6
  possible Digits for 4th place= 5
  possible Digits for 5th place= 4
  possible Digits for 6th place= 3
  possible Digits for 7th place= 2
  
  Total combination = 7*7*6*5*4*3*2 = 35280
• 11 years agoHelpfull: Yes(3) No(0)
• Answer is
  7*7!
• 11 years agoHelpfull: Yes(1) No(1)
• 1st place:- 0,3,9 are not allowed.so in 7 ways
  2nd place:- 3,9 and the no in first place is not allowed.so also in 7 ways
  3rd place:- 3,9,no in 1st place,no in 2nd place are not allowed.so in 6 ways
  so the answer is:-7*7*6*5*4*3*2=35280
• 11 years agoHelpfull: Yes(1) No(0)
• a seven digit no. can be formed from digits 0-9 excluding 3 and 9.
  
  
  7 * 7 * 6 * 5 * 4 * 3 * 2 = 35280 numbers Ans.
  _ _ _ _ _ _ _
• 10 years agoHelpfull: Yes(1) No(0)
• 6*6*5*4*3*2*1=4320
  
• 11 years agoHelpfull: Yes(0) No(4)
• 3528
  hello
• 11 years agoHelpfull: Yes(0) No(2)
• 7*7*6*5*4*3*2
• 11 years agoHelpfull: Yes(0) No(0)
• 1st place : 7 possibilities (excluding 0)
  2nd place : 7 possibilities.
  3rd place : 6 possibilities.
  Moving like this, answer will be 7*7*6*5*4*3*2=35280
• 10 years agoHelpfull: Yes(0) No(0)
• 1,2,4,5,6,7,8,0 Therefore
  7x7!=7x7x6x5x4x3x2x1=35280
  
• 10 years agoHelpfull: Yes(0) No(0)
• possible nos : 0-9 (10 values)
  omit 3 and 9 (8 values)
  non repeating 7digits: 8*7*6*5*4*3*2 = 40320 numbers
• 10 years agoHelpfull: Yes(0) No(0)
• ans:40320
  7 digit=8*7*6*5*4*3*2=40320
• 10 years agoHelpfull: Yes(0) No(0)
• 35280
  7*7*6*5*4*3*2=35280
• 10 years agoHelpfull: Yes(0) No(0)
• 35280;
  for 7th place there are 7 choices since we cant include 0,9and 3
  for 6th place also we have 7 choices since we can include 0
  similarly
  6,5,4,3,2 choices for rest
  so total numbers are 7*7*6*5*4*3*2=35280
• 10 years agoHelpfull: Yes(0) No(0)
• 423360.
  use permutations
  
• 10 years agoHelpfull: Yes(0) No(0)