If a die has 1 6 and 3 4 and 2 5 opposite each other how many such dies can

Let's take a blank die which has faces a,b,c,d,e,f (a,b),(c,d),(e,f) are opposite pair of sides (1,6),(3,4),(2,5) are 3 possible opposite side sets required These three can be arranged in above blank cube in 3*2 = 6 ways Each of these pairs can be arranged in 2 ways (1,6) or (6,1). Therefore Total number of dice possible = 6*2 = 12
13 years agoHelpfull: Yes(30) No(19)

I think there will be only 1 dice!!!
Imagine all the possibity, you will find all are actually same
10 years agoHelpfull: Yes(3) No(3)
my answer is 12.....is this correct...???
10 years agoHelpfull: Yes(3) No(0)
I think ans is 48
6*2*2*2
10 years agoHelpfull: Yes(2) No(4)
Let's take a blank die which has faces a,b,c,d,e,f

(a,b),(c,d),(e,f) are opposite pair of sides

(1,6),(3,4),(2,5) are 3 possible opposite side sets required

These three can be arranged in above blank cube in 3*2 = 6 ways

Each of these pairs can be arranged in 2 ways (1,6) or (6,1).

Therefore Total number of dice possible = 6*2 = 12
9 years agoHelpfull: Yes(2) No(0)
answer is 6 as (1,6) and (6,1) means the same
10 years agoHelpfull: Yes(1) No(2)
answer is 12
6 years agoHelpfull: Yes(1) No(0)
380-240=140
10 years agoHelpfull: Yes(0) No(3)
1,6 and 3,4 and 2,5 here given "and" all 3 must satisfy so only one
10 years agoHelpfull: Yes(0) No(1)
48
1 can placed in any of the 6 position, 2 can be placed in 4 position, 3 can be placed in remaining 2 position therefore
6*4*2=48
10 years agoHelpfull: Yes(0) No(1)
1,6( 4,3 3,4 2,5 5,2) 6,1 (3,4 4,3 2,5 5,2)
total number of dice possible =8
6 years agoHelpfull: Yes(0) No(0)
1,6 3,4 2,5
6,1 3,4 2,5
1,6 4,3 2,5
1,6 3,4 5,2
6,1 4,3 2,5
6,1 4,3 5,2
1,6 3,4 2,5

These three can be arranged in above blank cube in 3*2 = 6 ways

Each of these pairs can be arranged in 2 ways (1,6) or (6,1).

Therefore Total number of dice possible = 6*2 = 12
6 years agoHelpfull: Yes(0) No(0)

If a die has 1,6 and 3,4 and 2,5 opposite each other how many such dies can be made.