Find the sum of all three digit numbers that give a remainder of 4 when they are divided by 5
A)98720
B)99270
C)102090
D)None of these

• Answer is B)99270
  3 digit numbers range from 100 to 999.
  Out of these the numbers that will give remainder 4 when divided by 5 are..,
  104,109,114,...999
  this forms an A.P with a=104,tn=999 and d=5;
  To find n:
  tn=a+(n-1)d
  ==>999=104+(n-1)5
  ==>n=180
  Sum of n terms in an A.P is
  (n/2)*(a+l), where l is the last term.
  Substituting in formula,
  we get Sum=99270.........
• 11 years agoHelpfull: Yes(1) No(0)