the volumes of two spheres are in the ratio of 64:27. the ratio of their surface area is ?

• volume of sphere 4/3*pi*r^3
  1st sphere/2nd sphere=r^3/r^3=64/27
  Surface area 4*pi*r^2
  1st sphere/2nd sphere=r^2/r^2=16/09
  Since r=4 for 1st and r=3 for 2nd
  
• 11 years agoHelpfull: Yes(2) No(1)
• Ans=16:9
  If the Radius of two cylinders are R and r
  Volume of Sphere=(4/3)*Pi*r^3
  Given ratio Of Volume =64/27=V1/V2=R^3/r^3 or (R/r)=4/3
  Surface Area of Sphere=4*Pi*r^2
  Ratio of Surface Area=S1/S2=(R/r)^2=(4/3)^2=16/9
• 11 years agoHelpfull: Yes(1) No(0)
• 16:9 solve it
• 10 years agoHelpfull: Yes(0) No(0)
• ns=16:9
  If the Radius of two cylinders are R and r
  Volume of Sphere=(4/3)*Pi*r^3
  Given ratio Of Volume =64/27=V1/V2=R^3/r^3 or (R/r)=4/3
  Surface Area of Sphere=4*Pi*r^2
  Ratio of Surface Area=S1/S2=(R/r)^2=(4/3)^2=16/9
  
• 9 years agoHelpfull: Yes(0) No(0)