Q1.The remainder when (9)^19 + (6) is divided 8 is
Q2.The least five-digit perfect square number which id divisible by 3, 4, 5, and 8 is
Q3. What will be the remainder when 19100 is divided by 20?

• 1) 7
  2) 14400
  3) 0
  
  1) The remainder when any power of 9 divided by 8 is 1
  => 9^19 + 6 gives remainder of 1+6 = 7
  
  2) The number is multiple of (3^2)*(4)*(5^2)*(4)
  => n * 3600 = 14400
  
  3) As last two digits divisible by 20
  => remainder = 0
• 11 years agoHelpfull: Yes(6) No(1)