Elitmus
Exam
In a zoo there are 1 billion monkey.the probability tha monkey has seen a banana is 0.6 and prob that monkey has ssen a mango is 0.65.what is minimum percentage that monkey has seen both the trees?
25%,39%,40%or 60%
Read Solution (Total 5)
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- solu---> .6 * .065 = .39 ---> 39%
- 11 years agoHelpfull: Yes(17) No(6)
- 25%
Number of monkeys seen both the trees=(0.6+0.65)-1=0.25=25% - 11 years agoHelpfull: Yes(10) No(8)
- P(M sON BANANA)=0.6
P(MON MANGO)=0.65
since both are independent events
P(M intersection B)=P(M).P(B)
percentage that monkey sees both mango and banana=P(B).P(M)=0.39=39%
cheers - 11 years agoHelpfull: Yes(7) No(2)
- since both events are independent
total %=.65*0.60=0.39-->39% - 11 years agoHelpfull: Yes(5) No(2)
- 0.65*0.6=0.39=39%
- 10 years agoHelpfull: Yes(0) No(0)
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