Elitmus
Exam
Numerical Ability
Arithmetic
5 boxes are there viz. 1,2,3,4,5. We have blue balls and red balls. What is the probability of filling the boxes with no two consecutive blue balls?
Read Solution (Total 11)
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- 3/8
cases with consecutive blue balls can be categorised as:-
1)2 consecutive blue balls i.e BB => total cases with BB= 12
2)3 consecutive blue balls i.e BBB => total cases with BBB=5
3)4 consecutive blue balls i.e BBBB => total cases with BBBB=2
4)5 consecutive blue balls i.e BBBBB => total cases with BBBBB=1
total cases with consecutive blue balls =20;
so total case with no consecutive blue balls = 32-20=12
p=12/32=3/8
- 11 years agoHelpfull: Yes(19) No(10)
- edit:
there are two possibilities so= 2/32
= 1/16 - 11 years agoHelpfull: Yes(13) No(3)
- There are 13 cases in which 2 blue balls will not recur consecutively:
5 red => 1 case
4 red + 1 blue => (5!)/(4!) => 5 cases [BRRRR,RBRRR,RRBRR,RRRBR,RRRRB]
3 red + 2 blue => [(5!)/(3! 2!)] - [4!/3!] => 6 cases
2 red + 3 blue => 1 case [BRBRB]
total fav cases = 13
sample space = 2^5 = 32
probability = 13/32 - 11 years agoHelpfull: Yes(12) No(2)
- we have 5 boxes thus total possible outcomes are 2*2*2*2*2=32,and favourable outcomes include 2*1*1*1*1=2,thus probability = 1/16
- 11 years agoHelpfull: Yes(7) No(1)
- we can fill up in two ways i.e
1) R B R B R
2) B R B R B these are two favorable cases
and we have many red and blue balls, so each box has two choices either red or blue so, 2*2*2*2*2=32 ways are possible generally
therefore probability= 1/32 - 11 years agoHelpfull: Yes(5) No(6)
- ans is 13/32..........
- 11 years agoHelpfull: Yes(2) No(1)
- 1/16 is the correct soln.. is it????
- 11 years agoHelpfull: Yes(1) No(2)
- @ankita and vinod : YOU HAVE LEAVED CASES LIKE RRRRR,RRRRB,BRRRR,RBRRR,BRRRB,AND MANY MORE
- 11 years agoHelpfull: Yes(0) No(0)
- please elaborate the answer.....
- 11 years agoHelpfull: Yes(0) No(0)
- 4/5 bcoz in d problm stated that no two balls can be blue so, imagine two blue ball as one unit now it bcom units to fill it can be done in 4c3 ways i.e 4, now in remaning 3 can befilled with 3! ways i.e 6 .. so now boxes with two concequitive blue become 6*4=24... so now subtract these from total number of ways i.e total number of ways in which we can fill is 5! i.e 120 then we will get 96 so now probability bcomes 96/120=4/5
- 11 years agoHelpfull: Yes(0) No(5)
- @Anjul Bro please tell how did u get please once more clarify your answer :)
- 9 years agoHelpfull: Yes(0) No(0)
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