how many 5 digit no. can be formed with digits 1,2,3,4,5,6 that r divisible by 4 n digits are not repeated

• 192 ways
  
  To be divisible by 4,last two digits must be divisible by 4
  
  The possible last two digits are
  12,16,24,32,36,52,56,64
  
  => Total 5 digit numbers possible = 8*4! = 8*24 = 192 ways
  
• 10 years agoHelpfull: Yes(47) No(26)
• may be 192
  
  _ _ _ _ _
  4 3 2 1 (12,16,24,32,36,52,56,64)
• 10 years agoHelpfull: Yes(11) No(6)
• exactly 192
  last digit should be 12,16,24,32,36,44,52,56 for all individual combination is 24
  then total combination is 24*8=192
• 10 years agoHelpfull: Yes(10) No(3)
• The possible digits for last two positions are 12,16,24,32,36,44,52,56,64.
  The no. of ways for the first three positions (we need 5 digit number) will be 24, so we get 24*9=216 ways
• 10 years agoHelpfull: Yes(5) No(9)
• to be divisible by 4 ,last two digit must be divisible by4
  possible digits are
  12,16,24,32,36,52,56,64
  as we have to make 5 digit no. then the remaining 3 places can be filled in 4*3*2
  total possible no is 4*3*2*8=192
• 10 years agoHelpfull: Yes(1) No(1)
• 216 ways.
• 10 years agoHelpfull: Yes(0) No(10)