.10 men,10 women dance wid each other find d possibilty that 2 men r dancing with sme women n vice versa

• ans will be 0.
  becoz if 2 men dance with same women then one women will be single.
• 11 years agoHelpfull: Yes(4) No(1)
• n for cyclic hand shake and n-1 for linear handshake.
  so here no of hand shake is 23.
  
  OR
  
  Each person shakes hand with other.
  So 1 person will shake hand with 22 other people.
  There are total 23 people, so total number = 23*22
  but,if A shakes B, or B shakes A, its the same thing so divide that by 2 to get 23*22/2 = 253
  This is the maximum handshakes possible!
  Now, suppose there are 3 people : a, b and c
  So, cyclic handshakes(when they are seated in a circle) would be ab, bc and ac -> Thus only 3 hand shakes
  So, for 23 people, there would be 23 handshakes...
• 11 years agoHelpfull: Yes(1) No(1)
• possibility is zero...
• 11 years agoHelpfull: Yes(0) No(0)
• obviously 0 bcz they dance with each other
• 11 years agoHelpfull: Yes(0) No(0)