a speaks truth 80% B-60% probabilty a n b tell truth at same time

• (80/100)*(60/100)=0.48 or 48%
• 11 years agoHelpfull: Yes(13) No(3)
• a=80% b=60%
  
  a and b
  
  A intersection B
  
  80/100 x 60/100
  
  .8 x .6
  
  .48 --> 48 %
• 11 years agoHelpfull: Yes(7) No(0)
• probability that a speaks truth is 80/100=0.8
  probability that b speaks truth is 60/100=0.6
  both the probabilities are independent so the probability that a n b speaks truth at hte same time is 0.8*0.6=0.48
• 11 years agoHelpfull: Yes(3) No(0)
• probabilty A speeks truth 80/100
  probabilty B speeks truth 60/100
  req probabilty=(80/100)*(60/100)=0.48
• 11 years agoHelpfull: Yes(2) No(0)
• probability a speak truth = 0.8
  probability b speak truth = 0.6
  probability that both a and b speak truth = 0.8 * 0.6 =0.48
• 11 years agoHelpfull: Yes(2) No(0)
• 0.92
  p(aUb)=p(a)+p(b)-p(a^b)
  =p(a)+p(b)-p(a).p(b)
  =0.8+0.6-0.8*0.6
  =0.92
• 11 years agoHelpfull: Yes(1) No(8)
• 0.8*0.4=0.48
• 10 years agoHelpfull: Yes(1) No(0)
• 80% for a
  60% for b
  a&B= (1/2)*(80%+60%)
• 11 years agoHelpfull: Yes(0) No(4)
• p(AUB)=p(A)+p(B)-p(A^B)
  =p(A)+p(B)-p(A).p(B)
  =0.8+0.6-0.8*0.6
  =0.92
  
• 11 years agoHelpfull: Yes(0) No(6)
• (2/5)*(2/5)+(3/5)*(3/5)=0.52 answer.
• 11 years agoHelpfull: Yes(0) No(5)