. a man speaks 3 out of 4 times.he throws a dice n report it to be 6 what is probability of being 6

• man speaks truth 3 out of 4 times=3/4
  probability of getting 6 on throwing a dice is 1/6
  so reqd prob=(3/4)*(1/6)=1/8
• 10 years agoHelpfull: Yes(29) No(5)
• it should be speak truth 3 out of 4.
  prob. of true speak=3/4,prob.of flase speak=1/4
  prob. of getting 6=1/6
  prob. of not getting 6=5/6
  so prob=(3/4*1/6)/3/4*1/6+5/6*1/6
  ans=3/8
  
  
• 10 years agoHelpfull: Yes(9) No(7)
• GUYZ WHICH ONE 3/8
  OR 1/8
  M CONFUSED?????????????
• 10 years agoHelpfull: Yes(5) No(1)
• man speaks truth 3 out of 4 times, probability=3/4
  probability of man speaking false = 1-3/4 =1/4
  probability of getting 6 on dice=1/6
  probability of not getting 6 on a dice= 1-1/6 = 5/6
  therefore reqd probability= (3/4)(1/6)/ (3/4)(1/6)+(1/4)(5/6)
  = 3/8
  
• 10 years agoHelpfull: Yes(4) No(1)
• probability of being six is= 3/4*1/6
  =1/8
  
• 10 years agoHelpfull: Yes(3) No(2)
• probability of getting a die is=1/6
  and the speaks 3/4 times so
  probablity of being six=(1/6)*(3/4)=1/8
• 10 years agoHelpfull: Yes(2) No(2)
• 
  it should be speak truth 3 out of 4.
  prob. of true speak=3/4,prob.of flase speak=1/4
  prob. of getting 6=1/6
  prob. of not getting 6=5/6
  so prob=(3/4*1/6)/3/4*1/6+5/6*1/6
  ans=3/8
  
• 10 years agoHelpfull: Yes(2) No(3)
• options-A) 3/4
  B) 5/8
  C) 2/5
  D) 3/5
  E) 4/5
  Prob that its a 6 and he speaks truth :- 3/4 * 1/6 = 3/24
  
  Now what is the prob of reporting a 6 on a dice when it is a lie = 1/4 (speaking a lie) * 5/6 (prob of no. other than 6) * 1/5 (lieing the number as 6 and not telling any othe number except the actual no.) = 5/120 = 1/24
  
  Thus the prob of reporting no. as 6 (total lie + truth) = 3/24 + 1/24 = 4/24 = 1/6
  
  Thus prob of actually having 6 when reported so is = 3/24/1/6 = 3/4
  
  Answer A.
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• 3/4*1/6=1/8
• 10 years agoHelpfull: Yes(1) No(2)
• probability of getting 6 =1/6
  probability of a speaking truth =3/4
  so probability that a got 6 is= (3/4)*(1/6)= 1/8
• 10 years agoHelpfull: Yes(1) No(2)
• they asked only the probability of being 6.so i guess ans is 1/8
• 10 years agoHelpfull: Yes(1) No(1)
• If 6 actually appeared, he can report it with the probability of 3/4. If 6 has not appeared, still he can report it wrongly with the probability of 1/4
  So the probability that it is actually a 6 = (Probability to appear 6 x His truthfulness to report + Probability to appear any other number x His lieing probability ) = (1/6×3/4)+(5/6×1/4)=1/3
  The probability that it is actually 6 = (Probability that he reports 6)/(Total probability to appear 6)=(3/4×1/6)/((3/4×1/6)+(1/4×5/6))=3/8
• 10 years agoHelpfull: Yes(0) No(0)
• Prob that its a 6 and he speaks truth :- 3/4 * 1/6 = 3/24
  
  Now what is the prob of reporting a 6 on a dice when it is a lie = 1/4 (speaking a lie) * 5/6 (prob of no. other than 6) * 1/5 (lieing the number as 6 and not telling any othe number except the actual no.) = 5/120 = 1/24
  
  Thus the prob of reporting no. as 6 (total lie + truth) = 3/24 + 1/24 = 4/24 = 1/6
  
  Thus prob of actually having 6 when reported so is = 3/24/1/6 = 3/4
  
  
• 8 years agoHelpfull: Yes(0) No(0)