What will be the output of the program ?
#include

int main()
{
int i=3, *j, k;
j = &i;
printf("%dn", i**j*i+*j);
return 0;
}
Options
1) 30
2) 27
3) 9
4) 3

• i**j*i+*j means 3*(value of ponter j that is 3)*3+(value at pointer j which is again 3)
  so the result is 3*3*3+3
  30
• 9 years agoHelpfull: Yes(4) No(1)
• ans is not in the given option.
  exactly the ans is 30n.
  3*3*3+3=30 and also it print the 'n'.
  printf("%dn", i**j*i+*j);
• 9 years agoHelpfull: Yes(2) No(0)
• 1) 30
  because i=3 and *j=3
• 9 years agoHelpfull: Yes(0) No(0)
• The actual result is 3*3*3+3=30,
  but in the question ans is 30n
• 9 years agoHelpfull: Yes(0) No(0)
• 30, just assume *j as i because putting * infront of pointer makes use of value stored by that mem location
• 9 years agoHelpfull: Yes(0) No(0)
• Option-1
  output:= 30;
  because i=3;
  *j=3;
  (i)*(*j)*(i)+(*j)
  3*3*3+3=30;
  j stored address of variable i and *j stored the value of i (i.e. pointer concept )
• 7 years agoHelpfull: Yes(0) No(0)
• i * (*j) * i + (*j) = 3 * 3 * 3 + 3 = 27
• 6 years agoHelpfull: Yes(0) No(0)
• i**j*i+*j it means given i=3
  3*(3)*3+3=30
• 5 years agoHelpfull: Yes(0) No(0)
• i**j*i+*j means that 3*3*3+3=27+3
• 5 years agoHelpfull: Yes(0) No(0)