What is the average number of comparisons in a
sequential search?

• (N+1)/2
  N-size of array
  if element in first position then no of comparison will be 1
  or if the element is in last position then no of comparison will be N.
• 10 years agoHelpfull: Yes(8) No(0)
• if there are n number of elements in a sequence then there are n-1 no. of steps are required to search an element.
• 9 years agoHelpfull: Yes(0) No(0)
• Avarage number of comparision will be (N+1)/2(N-size of
  array).
  Because:If elements is in 1st position no of cpmparision
  will be one and if the element is in the last position then
  no of comparisions will be N.
• 6 years agoHelpfull: Yes(0) No(0)