find root of 2^3^4^(x)/4^3^2^x

• (2^3)^4^x/(4^3)^2^x=
  (8^4)^x/64^2^x=
  (64^x*64^x)/(64^x*64^x)=1
  its root will be 1
• 11 years agoHelpfull: Yes(3) No(1)
• ex:a^m/a^n=a^m-n
  so 2^12x/2^12x
  ->2^(12x-12x)
  ->2^0
  ->1
  so the answer is 1
  
• 11 years agoHelpfull: Yes(1) No(2)
• put x=0;
  =1/8
• 11 years agoHelpfull: Yes(1) No(3)
• root(4096^x/4096^x)=1
  
• 11 years agoHelpfull: Yes(1) No(0)
• 2^3^4^(x)/4^3^2^x = y
  Apply log
  log ((2^3^2)^2^x/(2^2^3)^2^x) = log y
  log 64^2^x/64^2^x = log y
  2^x log 64/64 = logy
  0 = log y (log 1 = 0)
  y = 1
  
• 11 years agoHelpfull: Yes(1) No(0)
• (((2^3))^4)^x)/
  (((4^3))^2)^x)
  X gets cancelled
  ((2^3))^4/((4^3))^2)= ((2^3)^2)/(4^3)=8^2/4^3=64/64=1
  
  
• 11 years agoHelpfull: Yes(1) No(0)