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Increase area of a square by 69%, and then by what percent should the side be increased?
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- if the prev. area was 100 sq. unit , we can take a side as 10 unit. if the area is now 169 sq. unit, then we can take a side as 13 unit. so , in 10 unit 3 unit is increased. so % of increase, 30 %.
- 11 years agoHelpfull: Yes(19) No(0)
- suppose side a=10
then area =a^2=100
69%incriease=100+69=169=(13)^2
now side=13 incriment=13-10=3 -> %incriease=(3/10)*100=30% - 11 years agoHelpfull: Yes(8) No(1)
- area of square is side*side
let x be the side
X*X=169/100--------->(69%=169/100)
x^2=13^2
so 130/100*130/100=169/100
the answer is 30%-------?(130/100=30%)
the side is increased by 30%
- 11 years agoHelpfull: Yes(7) No(0)
- 30%..BY AB METHOD
- 11 years agoHelpfull: Yes(1) No(0)
- 30%...because by AB method...A+B+AB/100...30+30+30*30/100
- 11 years agoHelpfull: Yes(0) No(0)
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