prove that the equation 6(x^2)-5x+1=0
has no integral solution

• [Sandeep Upadhyay]
  6x^2-3x-2x+1=0
  3x(2x-1)-1(2x-1)=0
  (3x-1)(2x-1)=0
  x=1/3 or x=/2
  1/3 and 1/2 are not integrals.
  Hence proved.
• 11 years agoHelpfull: Yes(1) No(0)
• 6x^2-3x-2x+1=0
  3x(2x-1)-1(2x-1)=0
  (3x-1)(2x-1)=0
  x=1/3 or x=/2
  Hence proved.
• 11 years agoHelpfull: Yes(0) No(0)
• 6x^2-5x+1
  x(6x-5)+1
  x=1/2
  1/2(3-5)+1
  1/2*2+1
  -1+1=0
• 11 years agoHelpfull: Yes(0) No(0)