A complets a race in 4min20sec. B completes same distance of 2km in 4min34sec. wat more distance can A travel in the meanwhile?

• A can complete a race of 2km in 260sec
  Time diff b/w A & B is 4min34sec-4min20sec => 14 sec
  A => 2000m => 260sec
  x => 14sec
  => x = 2000*14/260 =>107.6mts
  
• 11 years agoHelpfull: Yes(39) No(1)
• so,A can travel in 260sec a distance of 2km.
  in additional (4min34sec-4min20sec)=14sec he can travel...
  2*14/260=.107km
  so in the meanwhile A can travel 2107meters.
• 11 years agoHelpfull: Yes(8) No(7)
• 107.6 mtrs..................................................
  
• 11 years agoHelpfull: Yes(3) No(0)
• time taken by A=260sec
  time taken by B=274sec
  A reaches 274-260=14sec before B;
  SO extra distance covered by A is given by
  speed of A*time(14 sec)
  (2000m/260s)*14s=107.69230m
• 11 years agoHelpfull: Yes(1) No(0)