There is a five digit number, where the third number is one higher than the sum of first and second digits. Fourth digit is twice of fifth and third digit is twice the fourth. Second digit is five more than the first digit. What is the number?

• Ans : 16842
  
  Let the five digits number be ABCDE
  
  From given , C=(A+B)+1
  C =2D
  B=5+A >> C= A+5+A+1 =6+2A ...(1)
  D=2E >> C=4E ....(2)
  
  From eqn (2) , if we put E=1 we get C=4 and when sub C=4 in (1) , it won;t satisfy
  
  put E=2 in (2) , C=8 and sub C=8 in (1) ,it will satisfy and A= 1
  
  put E=3 in (2) , C=12 which is not acceptable
  
  Hence C=8, A=1,B=6,D=4,E=2 .
  
  Required Five digit number = 16842
• 13 years agoHelpfull: Yes(6) No(1)