P can run a kilometer in 4 min. 50 seconds and Q in 5 min. By what distance can P beat Q?

• P covers 1km(1000m) in 290secs.
  speed of Q = 1000/300 m/s
  =3.33 m/s i.e 3.33 m in 1 sec.therefore in 290 sec it covers 3.33*290 = 966.6657m
  => 1000-966.6657 =33.3343m
• 11 years agoHelpfull: Yes(37) No(2)
• P can cover 1000m in 290 sec
  Q covers 1000m in 300sec
  Q covers xm in 290sec
  => x = 1000*290/300
  => x = 966.66mts
  so P can beat Q by distance = 1000-966.66 = 33.34mts
• 11 years agoHelpfull: Yes(13) No(2)
• speed of P=1000m/290s
  P reaches 10 sec before Q,
  so the distance by which P beats Q is the covered by P in 10 seconds
  that is 1000*10/290=34.48275862 metres
• 11 years agoHelpfull: Yes(3) No(1)
• P covers 1000m in 290sec
  Q covers 1000m in 300sec
  Q covers 1000/300 =3.33 m in 1sec but in 290secs it covers 3.33*290=965.7m
  now 1000-965.7=34.3m
• 11 years agoHelpfull: Yes(2) No(0)
• P covers 1000m in 290sec
  Q covers 1000m in 300sec
  Q covers 1000/300 =3.33 m in 1sec but in 290secs it covers 3.33*290=965.7m
  now 1000-965.7=34.3m
• 11 years agoHelpfull: Yes(1) No(0)
• speed of Q=1000/30=3.33m/s
  in 290 sec it covers 3.33*290=966.55m
  so,1000-966.66=33.33m
  
• 11 years agoHelpfull: Yes(0) No(1)