a man leaves office daily at 7pm , a driver with car comes from his home to pick up him from office and bring back
home.one day he gets free at 5:30 pm....,instead of waiting for car ,he starts walking towards his home,on the way
he meets the car and returns home by car,he reaches home 20 minutes earlier than usual. In how much time does
he reach home usually ?

• Since the car has met the person 20 minutes before hand, it has actually saved 10 mins of journey (to and fro)
  
  since the man has started 1.30 hrs before and car has met him 10 mins before actual time he takes to reach daily is 1hr and 20 mins
• 10 years agoHelpfull: Yes(9) No(20)
• Since the car has met the person 20 minutes before hand, it has actually saved 10 mins of journey (to and fro)
  
  since the man has started 1.30 hrs before and car has met him 10 mins before actual time he takes to reach daily is 1hr and 20 mins
• 10 years agoHelpfull: Yes(1) No(12)
• can't be found.
  incomplete info's!
• 9 years agoHelpfull: Yes(0) No(2)
• If Man reaches to his house befour 20 minutes by his usual time ,means he meet his vehicle befour 10 min of his usual time. The distance walk by him in 1:30hr is equal to distance cover by the vehicle in 10 min. hence 1:30-0:10= 1:20 mins........means he reach at home by the 8:30PM usually
• 8 years agoHelpfull: Yes(0) No(0)
• cant find solution... plz help me how to find it.i cant understand
• 7 years agoHelpfull: Yes(0) No(0)
• If we assume that the man had called his driver(real world scenario generally anyone will do) at 5:30 and the driver leave the house at 5:30 then the time required to reach the office is 1hr 30 min because as given the man must meet the driver at 6:50 and it will take another 10 min to reach office by car so the total time required to reach the office from home by car is 1hr 30 min which is same as time required to reach home from office.
• 5 years agoHelpfull: Yes(0) No(0)