Probability of getting a total of 5 when 2 dice are thrown

• u ll get 5 n only these cases
  (2,3),(3,2),(1,4),(4,1) n total no of cases are 36 so 4/36=1/9
• 11 years agoHelpfull: Yes(7) No(0)
• 1/9.... because, there are 4 possibilities of getting a sum of five..... 1)1+4
  2)4+1.. 3)2+3... 4)3+2 out of a total probability of 36.... therefore, 4/36=1/9
• 11 years agoHelpfull: Yes(2) No(0)
• 1/9...(1,4),(2,3),(3,2),(4,1)
  hence 4/36 = 1/9
• 11 years agoHelpfull: Yes(1) No(0)
• when two dice are thrown n(s)=36 i.e{(1,1),(1,2),(2,1),(1,3),(3,1)etc..}
  event of getting total 5 ={(1,4),(4,1),(2,3),(3,2)}
  so P(e)=4/36
  =2/18
• 11 years agoHelpfull: Yes(0) No(0)