Q. What is the next number of the following sequence.

2,5,9,19,37,__

• Answer is 2,5,9,19,37,75,149,299....n so on....
  Given 1st number is 2....
  Steps :
  1. Multiply given number by 2.
  2. First increase the answer obtained from step 1 by one.
  3. The number which we get after 2nd step will be the next new number.
  4. Multiply this new number by 2.
  5. Decrease it by 1.
  6. The answer which we get in step 5 will be the next number.
  (again go to step 1 n do it to get further numbers)
  for the above question :
  first number is 2.
  1. Multiply by 2 = 4.
  2. Increase it by 1 = 5.
  3. So the next new number is 5. As given...
  4. Now multiply this new number i.e. 5 by 2 = 10
  5. By decreasing it by 1 = 9 .
  6. Hence we got the next new number of the series as 9.
  7. After this step we should follow the step 1 again taking the number as 9.
  So 9*2=18.....+1= 19.
  And 19*2=38.....-1=37...n so on...
  As shown if we follow the above explained steps , i hope, one can find the remaining numbers.....
• 11 years agoHelpfull: Yes(3) No(0)
• 2
  2 + 3 = 5
  5 + 4 = 9
  9 + 10 = 19
  19 + 18 = 37
  => next term = 37 + 38 = 75
  
• 11 years agoHelpfull: Yes(3) No(2)
• 2
  5 read as:2*2+1=5
  9 read as:5*2-1=9
  19 read as :9*2+1=19
  37 read as :19*2-1=37
  Similarly 37*2+1=75
  
• 11 years agoHelpfull: Yes(2) No(0)
• ans=75
  2*2=4+1=5
  5*2=10-1=9
  9*2=18+1=19
  19*2=38-1=37
  37*2=74+1=75
• 11 years agoHelpfull: Yes(1) No(0)
• ans : 75
  
  2,5,9,19,37
  2,2*2+1,5*2-1,9*2+1,19*2-1,37*2+1
  2,5,9,19,37,75
• 11 years agoHelpfull: Yes(1) No(0)
• 2^2-(2^1-0)=2
  2^3-(2^2-1)=5
  2^4-(2^3-1)=9
  2^5-(2^4-3)=19
  2^6-(2^5-5)=37
  2^7-(2^6-7)=71
  2^8-(2^7-9)=137
• 11 years agoHelpfull: Yes(0) No(0)
• ANS IS 75
  
  5-2=3 =>(2+1)
  9-5=4 =>(5-1)
  19-9=10 =>(9+1)
  37-19=18 =>(19-1)
  X-37=38 =>(37+1)
  
  X=75
  
• 11 years agoHelpfull: Yes(0) No(0)
• 75 2*5-1=9: 2*9+1=19: 2*19-1=37 and so the follow
• 11 years agoHelpfull: Yes(0) No(1)