Q. How many four-digit numbers,that are divisible by 4 can be formed, using the digits 0 to 7 if no digit is to occur more than once in each number

• 470
  last 2digts must be 04,12,16,20,24,32,36,40,52,56,60,64,72,76
  with 0's in last two digits:(04,20,40,60) - - --
  6*5*4 =120
  0 in middle: - - --
  5*1*10=50
  without any0:- - --
  5*4*10=200
  total 470
• 10 years agoHelpfull: Yes(1) No(1)
• there are 8 no.s possible.
  because the no. is divisible only if last two digits are divisible by 4.
  i.e __04,
  __12,
  __16,
  __20,
  __24,
  __32,
  __36,
  __40.
• 10 years agoHelpfull: Yes(0) No(4)
• for a no. to be divisible by 4, last two digits must be divisible by 24
  so last 2digts must be 04,12,16,20,24,32,36,40,52,56,60,64,72,76.
  total = 14
  in a 4 digit no. to end with 04
  the first digit has these many choices
  1,2,3,5,6,7 = 6 choices
  then obviously second digit has 6 choices
  3 & 4 digits must be 0 & 4 which is equal to 1 choice.
  therefore, for 04 ending nos., the chances are 6*6*1*1 =36.
  den for 14 types of ending 2 digit nos., there are 14*36=504 possibilities.
• 10 years agoHelpfull: Yes(0) No(0)