ind the remainder when 1234567891011.......40 when divided by 36???

• 28
  sum of digits = 820(41*40/2)
  last two digit 40 --> divisible by 4
  maintaining a sequential subtraction of 4 when we reach 123.........383912 sum=782(divisible by 9) , last two digit divisible by 4 , it means this number is divisible by 36 (9*4) , hence the remainder is 1234......383940 - 134.......383912 = 28
  
• 10 years agoHelpfull: Yes(0) No(1)