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Maths Puzzle
An equilateral triangle BPC is drawn inside a square ABCD. What is the value of the angle APD in degrees?
A] 75
B] 90
C] 120
D] 135
E] 150
Read Solution (Total 4)
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- http://totalgadha.com/file.php/1/moddata/forum/17/77681/New_Microsoft_PowerPoint_Presentation.jpg
- 9 years agoHelpfull: Yes(2) No(0)
- e 150
ab=bc=cd=ad=bp=bc - 11 years agoHelpfull: Yes(0) No(1)
- 150 PB=AB, So angle APB= 75,similarly angle CPD=75 & Angle BPC= 60 AS BPC is equilateral.
Angle APB=150 - 9 years agoHelpfull: Yes(0) No(1)
- PBC = ∠CPB = ∠BPC (equilateral triangle) and PC = CD = a.
CPD = ∠ PDC = 75 [(180 – 30)/2]
Similarly, ∠BAP = ∠BPA = 75
Hence ∠APD = 360 – (75 +75 + 60) = 150 - 7 years agoHelpfull: Yes(0) No(0)
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