Others
Maths Puzzle
The following data pertains to the profiles of 100 students who have appeared for the 'Selection Process' of a B-School, ISW College in the year 2009.
1. Each student has written exactly one of the two tests LAT or BAT, and every one of them has at least one of the two features - Good Academic Record (GAR) or Extra Curricular Activities (ECA).
2. No student who has written LAT has both GAR and ECA.
3. Sixty percent (60%) of the students who have appeared for the Selection Process have written LAT, of which 40% have Work Experience.
4. Fifty percent (50%) of the students who have appeared for the Selection Process have Work Experience, of which 30 students have GAR.
5. The number of students who have written BAT and also have both Work experience and GAR is 20.
6. The number of students who have written LAT and also have GAR is 25.
7. The number of students who have ECA but have no Work Experience is 35.
Note: The questions that follow are for the year 2009 only.
Q1. Out of all the students who have appeared for the Selection Process of ISW College, how many have written BAT and have Work Experience and GAR, but no ECA?
(a) 10 (b) 15 (c) 20 (d) Cannot be determined
Q2. Out of all the students who have appeared for the Selection Process of ISW College, what is the maximum possible number of students who have GAR and who have also written BAT but have no Work Experience?
(a) 10 (b) 12 (c) 14 (d) Cannot be determined
Q3. Out of all the students who have appeared for the Selection Process of ISW College, what is the total number of students who have written LAT and have ECA?
(a) 31 (b) 35 (c) 28 (d) Cannot be determined
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Others Other Question
Kamla fasted on 1st, 3rd, 6th, 10th, 15th...... day of the year 2010 and she continued fasting in this pattern thereafter. Bimla fasted on 1st, 4th, 8th, 13th, 19th..... day of the year 2010 and maintained the pattern thereafter. When would they fast together again?
(a) 23rd December, 2010 (b) 13th September, 2010
(c) 21st December, 2010 (d) Never
If
1 = 2
2 = 2
3 = 5
4 = 4
5 = ?
(Use proper logic)