A and B pick up a ball at random from a bag containing M red, N yallow and O green balls one after the other, replacing the ball everytime till one of them gets a red ball.The first one to get the red ball is declared as the winner.If A begins the game and the odds of his winning the game are 3 to 2, then find the ration M:N

• odds in favour of winning the event = (prob that an event will occur):(prob. that an event will not occur)
  if odds in favour of a winning the event is 3:2
  it means 3 if for red and 2 is for yelow and green.
  since the bag contains all three types so none can be zero.
  that means yellow:green =1:1.
  therefore M:N=3:1
• 11 years agoHelpfull: Yes(18) No(0)
• M/M+N+O = 3/5
  N+O/M+N+O = 2/5
  N+O=2
  so N=1
  answer is M:N = 3:1
• 11 years agoHelpfull: Yes(2) No(0)