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2 2 2=6

3 3 3=6

4 4 4=6

5 5 5=6

6 6 6=6

7 7 7=6

8 8 8=6

9 9 9=6
& prove it

• 2+2+2=6
  3*3-3=6
  sq.rt4+sq.rt4+sq.rt4=6 sq.rt=square root
  5+(5/5)=6
  6-6+6=6
  7-(7/7)=6
  sq.rt[(8+(8/8)]!=6 !=factorial 3!=6
  sq.rt 9*(sq.rt 9)-sq.rt 9=6
• 10 years agoHelpfull: Yes(11) No(2)
• 2+2+2 = 6
  3*3-3 = 9-3 = 6
  4+4-sq.rt(4)= 8-2 = 6
  5+5/5 = 5+1 = 6
  6+6-6 = 6
  7-7/7 = 7-1 = 6
  cube.rt(8) + cube.rt(8) + cube.rt(8)= 2+2+2 = 6
  sq.rt(9)*sq.rt(9)-sq.rt(9) = 3*3-3 = 6
• 10 years agoHelpfull: Yes(5) No(2)
• 2+2+2=6
  3+3/3^0=6
  (fact(4))/ 4/4^0=6
  5/5+5=6
  7-7/7=6
  8-8^0-8^0=6
  sqrt9 + sqrt9/9^0=6
  
  where ^ is power
• 10 years agoHelpfull: Yes(3) No(4)
• 2+2+2 = 6
  (3*3)-3=6
  4+4^0 +4^0=6
  5+(5-5)! =6
  (6+6)-6
  7-(7-7)!=6
  8-8^0-8^0=6
  (Sqrt (9*9) / Sqrt 9) !=6
• 9 years agoHelpfull: Yes(3) No(2)
• Do we apply any method to get answers?
• 4 years agoHelpfull: Yes(0) No(0)