CAT Exam

find the 2nd last digit of 48^300

Read Solution (Total 3)

(48)^300=(48^3)^100=(***92)^100=(***76)
thus , second last digit is 7
10 years agoHelpfull: Yes(2) No(2)

Answer is :76
10 years agoHelpfull: Yes(0) No(3)
48^300
((2^4)*3))^300
(2^4)^300*(3)^300 note:(2^10)^even=76 &(2^10)^odd=48 last 2 digits
2^1200*3^300
(2^10)^120*(3^4)^75 note:81^75=01 (ten place 0 because 8*5=unit olace is o)
76 * 01=76 last two digits
10 years agoHelpfull: Yes(0) No(0)

CAT Other Question

18 women complete a work in 12 days and 12 men can complete the same work in 9 days.in how many days will 8 emn and 8 women complete the work? Let f(x) = x^3 + p*x^2 + q*x + r, where p, q and r are natural numbers. If f(0) and f(–1) are both odd, then which of the
following is/are definitely true?

I. f(x) = 0 cannot have any integer roots.
II. f(x) = 0 has three distinct integer roots.
III.Roots of f(x) = 0 are imaginary.

A) Only II B ) I and III C) Only I D) Only III