. if a=bc then (a-b)^n-(c-b)^n+c^n for any value of n,the equation is always divisible
(a) bc (b) b but not c always
(c)c but not b always (d)non of above

• put n=1 then the given (a-b)^n-(c-b)^n+c^n is divisible by -> bc
  put n=2 then the given (a-b)^n-(c-b)^n+c^n is divisible by -> bc
  put n=3 then the given (a-b)^n-(c-b)^n+c^n is divisible by -> bc
  for for any value of n the given expression is divisible by bc
  option A
  
• 11 years agoHelpfull: Yes(13) No(2)
• Given (a-b)^n-(c-b)^n+c^n
  For any value of "n"..put n=1
  Now the question becomes (a-b)^1-(c-b)^1+c^1
  >>>>a-b-c+b+c
  >>>
  >>>>given a=bc
  >>>>bc....so,it is divisible by bc
• 11 years agoHelpfull: Yes(2) No(1)