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there are 2 boxes, one containing 32 red balls and other containing 31 green balls.You are allowed to move the balls between the boxes so that when u choose a ball at random and a ball at random from the chosen box, the probability of getting the red ball is maximised. This maximum probability is
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- ans:3/4=0.75
transfer 31 red balls in another box so that the first box contain 1 red ball and second box contains 31 green+31 red balls.
1/2*1 + 1/2*31/62 =3/4 - 11 years agoHelpfull: Yes(28) No(3)
- Shifting is allowed therefore shift 31 red balls to Box with green balls which makes it 1 red ball in 1st box and 31 red balls out of total 62 in 2nd box.
While finding probability we will also calculate probability of getting a box that is 1/2 of each.
so probability = (1/2)*1+1/2(31/62)= 3/4 - 11 years agoHelpfull: Yes(18) No(1)
- first to move the balls between two boxes we need to get the red ball only so the probability of choosing the box containing only red balls is 1/2 now choosing the red ball only is 32/63
so total probability is (1/2)*(32/63)=(16/63) - 11 years agoHelpfull: Yes(0) No(6)
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