If 13 = 13w/(1-w) ,then (2w)2 =

A.1/4 B.1/2 C.1 D.2

• 13=13w/1-w
  =>13(1-w)=13w
  =>1-w=w
  =>2w=1
  so,(2w)2=(1)2=2
  option D is the answer
• 13 years agoHelpfull: Yes(32) No(3)
• 13=13w/1-w
  13(1-w)=13w
  13-13w=13w
  13=26w
  w=13/26
  now for,(2w)2=(2*13/26)2=2
  so the ans. is 2
• 12 years agoHelpfull: Yes(9) No(2)
• 13=13w/1-w
  =>13(1-w)=13w
  =>1-w=w
  =>2w=1
  so,(2w)2=(1)2=2
• 10 years agoHelpfull: Yes(4) No(0)
• 13=13w/1-w
  =>13(1-w)=13w
  =>1-w=w
  =>2w=1
  so, (2w)2=(1)2 [** here it is 2w^2 and 1^2 **] {unconsciously many of them does it wrong}
  => (2w)2 = 1 [so option C IS CORRECT ]
• 6 years agoHelpfull: Yes(4) No(0)
• 13-13w=13w
  w= 1/2
  2*1/*2 = 2
• 10 years agoHelpfull: Yes(3) No(0)
• 13-13w=13w,
  26w=13,
  2w=1
  so putting the value of 2w in given equition
  (2w)*2=2*1=2
• 9 years agoHelpfull: Yes(3) No(0)
• 13w =13(1-w)
  w=1-w
  2w=1
  w=1/2
  so,(2w)2 =1
• 9 years agoHelpfull: Yes(1) No(11)
• 13(1-w)=13w
  13=13w+13w
  26w=13
  w=1/2
  2(1/2)2=2
• 8 years agoHelpfull: Yes(1) No(0)
• 13=13w/(1-w)
  w=1-w
  2w=1
  (2w)2=2
• 7 years agoHelpfull: Yes(0) No(0)
• if 13= 13w/ (1-w), Then (2w)^2=
  solution
  13 = 13w/ (1-w) cross multiply
  13w = 13(1-w)
  13w = 13 - 13w. collect like term
  13w + 13w = 13
  26w = 13
  W= 13/26, = 1/2
  substituting W in ( 2W)^2 = (2 x 1/2)^2 ( 2 cancels out = 1
  therefore = (1)^2= 1
• 5 years agoHelpfull: Yes(0) No(1)