There are 9 players including Mic and Jordan standing in a row. What is the probability of being 2 or less players between Mic and Jordan.

• total no. of ways arranging 9 people is = 9factorial.
  case-1--
  both sit together
  hence no. of ways of arranging them is 8fact*2fact.
  case-2
  1person sit between them
  hence no. of way of arranging them is 7(2fact*7fact).
  case--3
  2 person sit between them
  hence no. of ways arranging them is 7(2fact*6fact)
  hence total no. of ways ==8!2!+7(2!7!)+6(2!7!)
  divide this by 9!..
  ans.. 7/12
• 10 years agoHelpfull: Yes(23) No(5)
• 7/12....
  Simple one...
• 10 years agoHelpfull: Yes(17) No(8)
• @prerana
  the events of arranging 2 players in a row of 9= 9c2= 36
  the events when there will be 2 or less players between Mic and Jordan= 21
  so the probability of being 2 or less players between Mic and Jordan= 21/36 = 7/12
• 10 years agoHelpfull: Yes(5) No(8)
• @MOHIT AWASTHI the case whn 2 persons sit btw looks to be wrng...
  
  it shd be 7p2(2fact*6fact)
  
• 10 years agoHelpfull: Yes(5) No(0)
• explain it properly..plz
• 10 years agoHelpfull: Yes(1) No(7)
• please explain
• 10 years agoHelpfull: Yes(0) No(7)
• why are we multiplying by 7 in case 2 and 3 i.e in 7(2fact*7fact) ?? please explain
• 7 years agoHelpfull: Yes(0) No(0)
• In case 2 :
  Both Mic and Jordan with the 1person standing in between is taken as a combination and the others as 6 different arrangements.so total of 7.
  this can be done in 7 different ways.so multipying it with 7
• 7 years agoHelpfull: Yes(0) No(0)