Elitmus
Exam
Numerical Ability
Time Distance and Speed
A train having a length of 240 m passes a post in 24 seconds. How long will it take to pass a platform having a length of 650 m?
Options
1) 120 sec
2) 99 sec
3) 89 sec
4) 80 sec
Read Solution (Total 13)
-
- taken time to cross post=length of train/speed of train
so speed of train=240/24=10m/sec
time to cross platform=length of train+length of platform/speed of train
time=(240+650)/10=89sec ans
so option C is correct - 9 years agoHelpfull: Yes(6) No(0)
- this is not a elitmus level question
- 9 years agoHelpfull: Yes(4) No(0)
- 89 secs..i wish all other questions would have come of that level.:( ;)
- 9 years agoHelpfull: Yes(1) No(0)
- 89 sec is the right answer.
- 9 years agoHelpfull: Yes(0) No(0)
- Ans : 3) 89
- 9 years agoHelpfull: Yes(0) No(0)
- speed of train = 240/24 =10 m/s
time taken to pass platform = (length of train + length of platform ) / speed of train
=( 240 + 650 ) /10
=89 /10 =89 sec ------(c) - 9 years agoHelpfull: Yes(0) No(0)
- Speed = Distance/Time = 240/24 = 10.
While Passing from Platform , 650m long
Distance = 240 + 650
time= distance/speed = 890/10 = 89 - 9 years agoHelpfull: Yes(0) No(0)
- speed=240/24=10
650+240=890
t=890/10
t=89 - 9 years agoHelpfull: Yes(0) No(0)
- 24=240/u
u=10m/s
time=240+650/10
time=890/10
time=89sec - 9 years agoHelpfull: Yes(0) No(0)
- 3) 89 sec
first find speed=distance/time
speed=240/24
speed=10m/s
after that get time for passing platform =(240+650)/10
ans- 89 sec - 9 years agoHelpfull: Yes(0) No(0)
- total length=650+240=890
speed=240/24=10m/s
time=890/10=89 sec
- 8 years agoHelpfull: Yes(0) No(0)
- 89 secs
65 secs to reach end + 24 secs to cross = 89 secs - 5 years agoHelpfull: Yes(0) No(0)
- Speed of train = 240/24 = 10m/s
Time taken by train to cross platform = (650+240)/10 = 89sec
So correct option is c. - 4 years agoHelpfull: Yes(0) No(0)
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