On a 26-question test, five points were deducted for each wrong answer and eight points were added for each correct answer. If all the questions were answered, how many were correct if the score was zero?
A. 10
B. 11
C. 12
D. 13

• if x no. of question is wrong and y no. of question is correct then
  -5*x+8*y=0 and x+y=26
  by solving we get
  x=16 & y=10
• 11 years agoHelpfull: Yes(43) No(2)
• 10 questions were correct x 8 points each = +80 points.
  16 questions were wrong x 5 points each = -80 points
  Total = 0 points
• 11 years agoHelpfull: Yes(20) No(1)
• x=no of wrong ans;
  y=no of right ans;
  x+y=26;
  5x=8y;
  solving y=10
• 11 years agoHelpfull: Yes(9) No(0)
• ans=10
  go through the options
  if i select 1st option then
  10*8-16*5=0
  
• 11 years agoHelpfull: Yes(4) No(0)
• Let x questions are correct=>26-x questions are wrong
  From question
  =>8x-(26-x)*5=0
  =>13x=130
  =>x=10
  
• 11 years agoHelpfull: Yes(4) No(0)
• If the score was zero then it means the marks of correct questions = marks of incorrect questions.
  Since correct questions will be awarded 8.so if out of 26 questiions 10 were correct , then
  marks for correct 10 questions = 10*8= 80
  For each incorrect question 5 marks will be deducted ,
  and we know for a total zero incorrect marks = correct marks
  so he attempted 16 incorrect questions.
  because 16*5 =80
  so his net score will be zero
• 11 years agoHelpfull: Yes(2) No(0)
• Ans is 10
  please go through the answer
  10*8=80
  16*5=80
  80-80=0
• 10 years agoHelpfull: Yes(2) No(0)
• let no. of questions correctly answered be c nd wrongly answered be w...
  c+w=26
  8c-5w=0
  solving we get....c=10...i.e....A answer
• 11 years agoHelpfull: Yes(1) No(0)
• ans=A (10)
  let wrong answers be: x
  so correct answers=(26-x)
  we get the eqn: 8(26-x)-5x=0; so x=26, correct answers = 26-x = 10
  
• 11 years agoHelpfull: Yes(1) No(0)
• let no. of questions answered correct be x,awarded score is 8*x
  no. of questions answered wrong are (26-x),awarded score is -5*(26-x)
  =>[8*x]-[5*(26-x)]=0,
  =>13*x=26*5,
  =>x=10.
  
• 11 years agoHelpfull: Yes(1) No(0)
• let x be the no of correct answers then,(26-x) will be no of wrong answer's
  as 8 points were given for each right answer so,8*x-5*(26-x)=0
  =>8x+5x=130 ,x=10 ans
  -ve sign is taken as marks is deducted
• 11 years agoHelpfull: Yes(1) No(0)
• 12*8-16*6=0
• 11 years agoHelpfull: Yes(0) No(2)
• answer in 10 becouse 10 answer is correct and 16 answer is wrong then 16*5=80
  10*8=80
• 11 years agoHelpfull: Yes(0) No(0)
• Let wrong questions be y and correct ques be x
  so 8x-5y=0.....eq(1)
  also x+y=26 (given)
  =>x=26-y.....eq(2)
  
  from eq(1) and eq(2)
  wrong,y=16
  correct,x=10
  
• 11 years agoHelpfull: Yes(0) No(1)
• since the final score was zero ,,both correct answer and wrong answer should cancel each other ,so it will be a common multiple between 5 and 8,,there will 4 options 5(5*8=40),10(10*8=80),15(15*8=120),20(20*8=160),,if 5 answer are correct then wrong answers will not be balanced(21*5=105),,if 10 answers are correct then wrong answers will tally the score to zero(16*5=80) (80-80=0) so the no. of correct answers are 10
• 11 years agoHelpfull: Yes(0) No(0)
• 10 will b the answer
  
• 11 years agoHelpfull: Yes(0) No(0)
• answer is 13
  
  
• 11 years agoHelpfull: Yes(0) No(4)
• answer will be 10 as we see if he give 16 wrong answer then it equals to 10 right answer.means 80=80//
  
• 11 years agoHelpfull: Yes(0) No(0)
• let x be correct ans so 26-x is the wrong ans
  8*x- (26-x)*5=0
  =>8*x+5*x=130
  x=130/13
  x=10
• 11 years agoHelpfull: Yes(0) No(1)
• no.of right questn attempted is x and no of wrong questn attempted is y.
  y*8-5*x=0 and y+x=26
  on solving we get
  x=10 and y=16
• 11 years agoHelpfull: Yes(0) No(0)
• only 10 ans are correct . using hit and trail method .
• 11 years agoHelpfull: Yes(0) No(0)
• 26*5=130 is wrong mark= -130 -ve mark
  26*8=208 is correct mark
  so [208-(-130)]/26 = 13
  8-5=3
  so 13-3 =10 (A)
• 11 years agoHelpfull: Yes(0) No(0)
• if we go through options it is easy for us to find out the correct questions.
  go from 1st option.....if 10 were correct then 16 must be wrong (26-10)....
  as per given marks is 0......we conclude that 10*8-16*5=0....so option a...
• 10 years agoHelpfull: Yes(0) No(0)
• let no. of correct answers be 'X'
  so, no. of wrong answers= (26-X)
  Now A/q
  8X - 5(26-X)=0
  by solving equation we get,
  X= 10
  so, option (A) is correct
• 9 years agoHelpfull: Yes(0) No(0)
• assume x questions are correct.so, 8*x-(26-x)*5=0
  so ans is 10
• 8 years agoHelpfull: Yes(0) No(0)
• option verification 10
• 8 years agoHelpfull: Yes(0) No(0)
• 10 consider correct ans =10
  wrong ans=16
  (10*8)-(16*5)=0
  so ans=10
• 8 years agoHelpfull: Yes(0) No(0)
• x*8-y*5=0
  by verifying options we get answer as 10
• 8 years agoHelpfull: Yes(0) No(0)
• Let x ques were correct. Therefore, (26- x) were wrong
  8x−5(26−x)=0
  Solving we get x=10
• 7 years agoHelpfull: Yes(0) No(0)
• Answer is 10
• 6 years agoHelpfull: Yes(0) No(0)
• sol :
  
  5 points are deducted if the question is wrong = (-5) x
  
  8 points are awarded if the question is correct = 8y
  
  8y+ (-5x) = 0
  
  8y = 5x
  
  y= 5x8
  sub 'y' in x + y = 26
  
  x= 16, y = 10 Hence 10 are correct
• 6 years agoHelpfull: Yes(0) No(0)
• 10
  8*10=80 80 no. for correct
  And rest 16 que are wrong so
  16*5=80 no. deduct for wrong ans
  So overall no is zero
• 6 years agoHelpfull: Yes(0) No(0)
• Let x be number of questions answered correctly
  then 26-x will be number of questions answered wrongly
  then,
  8*x-5*(26-x)=0 (since the score was zero we equate it to zero)
  by solving the above equation we get x value as 10
• 5 years agoHelpfull: Yes(0) No(0)
• Since, N=k*LCM(4,5,6) - d
  where d is difference between the divisor and remainder(i.e. 4-2=5-3=6-4=2=d)
  Therefore, N= 60k+2 (k=1,2,3,4,5,6)
• 5 years agoHelpfull: Yes(0) No(0)
• 10
  x=no of right ans
  y=no of wrong ans
  x+y=26
  8x+y(-5)=0
  solving these two
  x=10
  total 10 are correct
• 3 years agoHelpfull: Yes(0) No(0)
• 16*5=80
  10*8=80
  so,
  ans:10
• 3 years agoHelpfull: Yes(0) No(0)